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4x^2+8x+3=899
We move all terms to the left:
4x^2+8x+3-(899)=0
We add all the numbers together, and all the variables
4x^2+8x-896=0
a = 4; b = 8; c = -896;
Δ = b2-4ac
Δ = 82-4·4·(-896)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-120}{2*4}=\frac{-128}{8} =-16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+120}{2*4}=\frac{112}{8} =14 $
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